Question

after rationalizing the denominator of 7/3root3-2root2 the denominator will be?​

Answer 1

Answer:

$7 \div 3 \sqrt{3} - 2 \div \sqrt{2 }$

by rationalization

$7 \times 3 \sqrt{3} \div 3 \sqrt{3} \times 3 \sqrt{3} - 2 \times \sqrt{2} \div \sqrt{2} \times \sqrt{2}$

$21 \sqrt{3 } \div 27 - \sqrt{2}$

$21 \sqrt{3 } - 27 \sqrt{2} \div 27$