Question

after rationalizing the denominator of
The surd 12/
(3+√5 + 2√2)
the denominator becomes,
(a) √5 -√2 + √10+1
B) √5 +√10+√2+1
(c) √10 + √2 + √5 +1
(d) √5-√10-√2-1
​

Answer 1

Step-by-step explanation:

after rationalizing the denominator of The surd 12/ (3+√5 + 2√2) the denominator becomes ... - did not match any documents.

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Answer 2

Answer:

$\sqrt{5} - \sqrt{10} + \sqrt{2} + 1$

hope you got it