Question

After simplifying, [7(81/3 + 1251/3)]1/4 we get​

Answer 1

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$[\:(7\frac{8}3} + \frac{1251}{3})\:] \frac{1}{4}$

$\red{\underline{\sf{SolutiOn-}}}$

⇒ We are going to solve the sum by the BODMAS method.

= $(7\frac{8}3} + \frac{1251}{3}) - \frac{1}{4}$

=  $\frac{7\:\times\:3\:+\:81}{3} + \frac{1251}{3} - \frac{1}{4}$

= $\frac{102}{3} + \frac{1221}{3} - \frac{1}{4}$

= $\frac{102\:+\:1251}{3} - \frac{1}{4}$

= $\frac{1324}{3} - \frac{1}{4}$

= $\frac{1324\:\times\:1}{3\:\times\:4}$

= $\frac{1324}{12}$

${\fbox{\red{1325/12}}}}$

Answer 2

$[\:(7\frac{8}{3} + \frac{1251}{3})\:] \frac{1}{4}$

$\red{\underline{\sf{SolutiOn-}}}$

⇒ We are going to solve the sum by the BODMAS method.

= $(7\frac{8}{3} + \frac{1251}{3}) - \frac{1}{4}$

= $\frac{7\:\times\:3\:+\:81}{3} + \frac{1251}{3} - \frac{1}{4}$

= $\frac{102}{3} + \frac{1221}{3} - \frac{1}{4}$

= $\frac{102\:+\:1251}{3} - \frac{1}{4}$

= $\frac{1324}{3} - \frac{1}{4}$

=$\frac{1324\:\times\:1}{3\:\times\:4}$

= $\frac{1324}{12}$

$\huge{\fbox{\red{1325/12}}}$