After some displacement the position vector is given as 3t i cap + 4sin t j cap metre then find acceleration equals to how much when time given equal to pi by 6 seconds
Answers
Answered by
1
Answer:
ANSWER
r
=(t
2
−4t+6)
i
^
+(t
2
)
j
^
velocity =
dt
dr
=(2t−4)
i
^
+(2t)
j
^
acceleration =
dt
dv
=(2)
i
^
+(2)
j
^
a
.
v
=((2t−4)
i
^
+(2t)
j
^
).((2)
i
^
+(2)
j
^
)
when they are perpendicular then a.v = 0
((2t−4)
i
^
+(2t)
j
^
).((2)
i
^
+(2)
j
^
)=0
(2t−4)×2+4t=0
4t−8+4t=0
t=1s
solution
I hope it helps you
please like and follow me
please mark as brilliant answer
Similar questions