Question

After this...????
Help me out..
Please

Answer 1

Step-by-step explanation:

let x/y be the fraction

1)(x+2)/y=2/3

2)x/(y+4)=4/7

1)3(x+2)=(2y) /3

3(3x+6)=2y

9x-2y+18=0. equation 1

2)7x=4(4+y)

7x=16+4y

7x-4y-16=0

multiply (2) by 2

therefore 18x-4y+36=0(3)

now subtract 3 and 2

11x-52=0

x=52/11

substitute x=52/11 in(1)

9(52/11)-2y=-18

468/11-2y=-18

-2y=-18-(468/11)

2y=(198+468)/11

2y= 666/11

y=666/22

y=333/11