Question

After time t, the height 'y' of a projectile is y = 8t– 5t^2and horizontal distance x = 6t. If g = 10m/s.
the velocity of projectile at the instant of projection is
a) 8 m/s
b) 10 m/s
c) 6 m/s
d) 4 m/s
In a proiectie motion if the maximum height is equal to the horizontal range, the angle of projections
16​

Answer 1

Answer:

B

Explanation:

In this question given that position of body at both axis x and y . and using these information calculate velocity of body on both axis at t=0 and take resultant

Answer 2

Explanation:

answer is option b

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