Math, asked by mdkaif2776gmailcom, 9 months ago

After traveling for 1 hour a train met with an accident and was detained for 1 hour.Then it travelled with a speed equal to 3/5th of the original speed and reached the destination 3 hours late .Had the place of accident been 50 km after the previous place the train would have reached the destination 1 hour 20 minutes earlier than before.What was the total distance travelled by the train and what was it's original speed?​

Answers

Answered by alokmishraivps007
1

Answer:

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Step-by-step explanation:

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Answered by pandeydiksha219
1

Answer:

Distance =360

If x is the original speed, then difference in time =

(3x/5)

360

x

360

=4

Solving, we get x=60 km/hr

If T is the total hrs, then

60T=150+60×

5

3

×(T+8−2.5)

Solving, we get T=14.5 hrs

and distance =60×14.5=870 km

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