After traveling for 1 hour a train met with an accident and was detained for 1 hour.Then it travelled with a speed equal to 3/5th of the original speed and reached the destination 3 hours late .Had the place of accident been 50 km after the previous place the train would have reached the destination 1 hour 20 minutes earlier than before.What was the total distance travelled by the train and what was it's original speed?
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Answered by
1
Answer:
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Step-by-step explanation:
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Answered by
1
Answer:
Distance =360
If x is the original speed, then difference in time =
(3x/5)
360
−
x
360
=4
Solving, we get x=60 km/hr
If T is the total hrs, then
60T=150+60×
5
3
×(T+8−2.5)
Solving, we get T=14.5 hrs
and distance =60×14.5=870 km
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