Question

After two successive increases of 25%, the price of
petrol is Rs 52 per little. What wa
s the price/liter of
petrol initially?
1) Rs 43.28 2) Rs 33.28 3) Rs 23.82
4) 25.23
5) None of these
d by 200​

Answer 1

Step-by-step explanation:

successive percentage = x+y+x×y/100

x= 25 y=25

By solving in equation we get,

successive increase percentage = 56.25

Increased rate of petrol = 52/ltr

156.25 == 52

100 == 33.28

Answer 2

Answer:

The price/liter of petrol initially is 33.28 rupees.

So, option 2 is the right answer.

Step-by-step explanation:

Here given,After two successive increases of 25%, the price of petrol is Rs 52 per liter.

Let initially cost of the petrol be x rupees.

Now price of petrol increase 25%.

We know a% of b means

$\frac{a}{100} \times b$

and a% increase of b means

$= \frac{100 + a}{100} \times b$

Here first cost of petrol increase 25 % of initially cost of petrol = Increase 25 % of x

$= \frac{100 + 25}{100} \times x\: rupees$

and again cost of petrol increase 25%

So now cost of petrol

$= \frac{100 + 25}{100} \times \frac{100 + 25}{100} \times x \: rupees$

According to question,

$\frac{100 + 25}{100} \times \frac{100 + 25}{100} \times x = 52 \\ \frac{125}{100} \times \frac{125}{100} \times x = 52 \\ \frac{5}{4} \times \frac{5}{4} \times x = 52 \\ x = 52 \times \frac{4}{5} \times \frac{4}{5} \\ x = 33.28$

So, initial cost of petrol was 33.28 rupees.

This is a problem of percentage.

Know more about percentage,

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