Question

After5years fathers ege will be three times his sons age, while5years ago fathers agewas 7times his sons age find their preasent age.​

Answer 1

Answer:

father's age 40 & son-s age 10

Step-by-step explanation:

Let the father present age =x years and son present age =y years

According to the first condition

5 years later father will be (x+5) years old and son will be (y+5) years old.

⇒x+5=3(y+5)

⇒x+5=3y+15⇒x=3y+10....eq1

According to the second condition

5 years ago father was (x−5) years old and son was (y−5) years old.

⇒x−5=7(y−5)

⇒x−5=7y−35

⇒x−7y=−30....eq2

Put the value of x from eq1

⇒3y+10−7y=−30⇒−4y=−40⇒y=10

Put y=10 in eq1

⇒x=3×10+10=40

Hence, Father present age =40 years

Son present age =10 years

Answer 2

Step-by-step explanation:

Father's age Sons age

5yrs ago 7x x

present age 7x+5 x+5

5yrs hence 7x+10 x+10

3times sons age = fathers age

3(x+10)= 7x+10

3x + 30=7x+10

30 -10=7x-3x

20 = 4x

x= 5

Present age of son is 10 yrs and Father's is 40 yrs