Question

afternoon zeros of polynomial 9 x raised to 4 minus 6 x cube minus 35 X square + 24 x minus 4 if two of its zeros are 2 and minus 2

Answer 1

as the zeroes of the polynomial are 2 & -2
it's factors will be (x-2)(x+2)
=
$x {}^{2} - 4$
Now,
p(x) =
$p(x) = 9 x{}^{4} - 6x {}^{3} - 35 {}^{2} + 24x - 4$
A/q:-
(see the division at the top)*
Now factorise the quotient by middle term splitting.
we get x=1/3 & 1/3
Hence,
Zeroes of the polynomial are 1/3,1/3,2.-2.