Math, asked by anagamashish, 3 months ago

Afzal sat for aptitude certification exam. The exam had no negative marking. He correctly attempted 18 questions and got 110 marks. Questions were of two types. Type A awarded 10 marks and Type B awarded 3 marks to him. Can you tell us the total marks of another lot of 18 questions in which number of correctly attempted Type A and Type B questions by Afzal are interchanged?

Answers

Answered by amitnrw
0

Given :  correctly attempted 18 questions and got 110 marks.

. Questions were of two types. Type A awarded 10 marks and Type B awarded 3 marks to him.

To Find : total marks of another lot of 18 questions in which  number of correctly attempted Type A and Type B are interchanged

Solution:

Type  A  = x  

Type B = 18 - x

Type A  Marks  = 10x

Type B Marks  = 3(18 - x) = 54 - 3x

10x + 54 - 3x = 110

=> 7x = 56

=> x = 8

Type  A  = 8

Type B = 10

Interchanged

Type  A  =10

Type B = 8

Marks = 10 (10) + 3(8)

= 100 + 24

= 124

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