Again a question.. Hope somebody will answer..
x and y be two positive real numbers such that x²+9y²=369 and xy=60 , find the value of x- 3y. (Step by step)
Answers
Answered by
8
x² + 9y²= 369
xy=60
(x-3y)² = x² + (3y)² -6xy
= x² + 9y² -6(60)
=369 -360
=9
x-3y=√9
x-3y= 3
xy=60
(x-3y)² = x² + (3y)² -6xy
= x² + 9y² -6(60)
=369 -360
=9
x-3y=√9
x-3y= 3
amrtanshu10Amrtanshu:
Pls mrk as brainliest nswer
Idk hw to do so.. :(
By the way thanks ..
Can u tell me hw to mark it as brainliest ??as I want to..
Thank you :)
Answered by
9
hope this will help you......
Attachments:
Thanks for the answer..!!
Similar questions