Question

again I have posted this question please answer properly​

Answer 1

To find:-

•Value of <A+<B+<C+<D+<E+<F

Solution:-

By Angle Sum Property of a triangle,we know that sum of 3 angles of a triangle is 180°

In triangle ACE:-

=><A+<C+<E=180° ------(1)

In triangle BDF:-

=><B+<D+<F=180° ------(2)

Now,by adding equation (1) and (2),we get------

=>(<A+<C+<E)+(<B+<D+<F)=180°+180°

Thus----

=><A+<B+<C+<D+<E+<F=360°

Answer 2

angle A+ angle C+ angleE = 180° (ASP)

angle B+ angle D+ angleF = 180° ( ASP)

ASP = Angle sum property of triangle = 180°

take first equation

A+C+E = 180° ( there are three angles )

3 angles = 180°

= 180÷3

= 60°

so angle A = 60° , C = 60° , E = 60°

same for second equation

so angle B = 60°, D = 60°, F = 60°

angles A,C,E,B,D,F = 60°

You can confirm that by a definition

( sum of all exterior angles is 360° )

add 60°+60°+60°+60°+60°+60°= 360°