Question

against
A 15 m long ladder reached a window 12 m
high from the ground on placing it
a wall at a distance a find the distance
of the foot of the ladder from the
wall.​

Answer 1

Let AC be the ladder and A be the window.

Given: AC=15m, AB=12m, CB=am

In right angled triangle ACB,

(Hypotenuse) ^2 =(Base) ^2 +[Perpendicular) ^2

[By Pythagoras theorem]

⇒(AC) ^2 =(CB) ^2 +(AB) ^2

⇒(15) ^2 =(a) ^2 +(12) ^2

⇒225=a ^2 +144

⇒a ^2=225−144=81

⇒a^2= 81

=9cm

Thus, the distance of the foot of the ladder from the wall is 9m.

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