Question

Agar kisi particle ko building ke top se vertically upward direction mein feke jaye to uska displacement to height of building hona chaihiye yes or no.

Answer 1

Answer:

this is question or not

Answer 2

the answer is . Taking upward direction to be positive.

Initial velocity of particle is u

Final velocity of particle at the maximum point v=0

Let time taken to reach maximum height be t

1

.

Using v=u−gt

∴ 0=u−gt

1

⟹ t

1

=

g

u

Using S=ut−

2

1

gt

2

2

where S=−H and t

2

is the time taken by particle to hit the ground.

∴ −H=ut

2

−

2

1

gt

2

2

Given : t

2

=nt

1

⟹ t

2

=

g

nu

Or −H=u×

g

nu

−

2

g

×(

g

nu

)

2

We get 2gH=nu

2

(n−2)

Option C is correct.

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