Question

AgCl/Ag* can be most easily coagulated by least concentration of

Br^-

co3^2-

PO4^3-

[Fe(CN)6]4-​

Answer 1

Answer:

fe(cn)6]4-

Explanation:

because of high power

Answer 2

$AgCl/Ag*$ can be most easily coagulated by the least concentration of $[Fe(CN)6]4-$

Explanation:

• $AgCl/Ag*$ can be most easily coagulated by the least concentration of $[Fe(CN)6]4-$
• According to Hardy Schulze law,  When higher is the positive charge on the metal atoms, then more will be the tendency of a metal atom so as to cause coagulation of negatively charged colloid.
• AgCl/Ag+  is a positively charged sol. Thus the electrolyte which has maximum negative charge will be the most effective electrolyte. So ​$[Fe(CN)6]4-$ will be the most effective electrolyte for the coagulation to take place.