age A year more than B is the same of same of there age is 45 year find the age of both ?
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Answered by
1
45=A+B
A=3,B=5 value
A= 45 /3 ,15×3= 45
B = 45/5 ,5×9 = 45
since we find age of A and B
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Answer:
Let the members be Old Having age O + other 9 having ages x and New one having age Y
Sum of their ages = (Y + 9 × x) and average = (Y + 9 × x)/10
Before 4 years sum was (O + 9 x – 10 × 4) and average = (O + 9 x – 10 × 4) /10
equating, Y + 9 x = O + 9x – 40
Y = O – 40
Younger is 40 years younger than Old
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