Age of a father is 3 times the sum of ages of his two sons. 5 years hence age of father will be two times the sum of ages of his two sons find present age of father.
Answers
Given :
- Age of a father is 3 times the sum of ages of his two sons.
- 5 years hence age of father will be two times the sum of ages of his two sons.
To find :
- Present age of father.
Solution :
Consider,
- Age of father = x years.
- Age of 1st son = y years.
- Age of 2nd son = z years.
According to the 1st condition :-
- Age of a father is 3 times the sum of ages of his two sons.
According to the 2nd condition :-
- 5 years hence age of father will be two times the sum of ages of his two sons.
After 5 years,
- Age of father = (x+5) years
- Age of 1st son = (y+5) years
- Age of 2nd son = (z+5) years
- Now put y+z = 20 in eq[1].
Therefore, the present age of father is 45 years.
Present age of man is 45 years.
Given :-
The age of a man is three times the sum of the ages of his two sons.
5 years hence, his age will be double the sum of their ages.
To find :-
Present age of man.
Solution :-
Let ,
Man's present age = x years
Present age of 1st son = y years
Present age of 2nd son = z years
The age of a man is three times the sum of the ages of his two sons.
➪ x = 3(y+z)
➪ y+z = x/3 ..................(i)
5 years hence, his age will be double the sum of their ages
5 years hence,
Man's age = (x+5) years
Age of 1st son = (y+5) years
Age of 2nd son = (z+5) years
➪ x+5 = 2[(y+5)+(z+5)]
➪ x+5 = 2(y+z+10)
[ put y+z = x/3 from eq (i)]
➪ x+5 = 2(x/3 + 10)
➪ x+5 = 2x/3 + 20
➪ x - 2x/3 = 20-5
➪ x/3 = 15
➪ x = 45
† Present age of man is 45 years.