Question

Age of A is 20 years less than the age of B. Age of B is thrice the age of C. Age of C is half the age of D. Age of D is 38 years. what is the age of B?​

Answer 1

Answer:

Given,

Age of 'D' = 38 years

Age of 'C' = Half the Age of D

Age of 'B' = Trice the age of 'C'

Age of 'A' = 20 years less than Age of 'B'.

To Find :-

Age of 'B'.

Solution :-

Given,

1)Age of 'C' = Half the Age of 'D'

Age of 'D' = 38 Years.

$\sf\implies Age \: of \: 'C' = \dfrac{38 Years}{2}$

Age of 'C' = 19 years.

$\sf\therefore Age\: of\: C = 19Years$

2) Age of 'B' = Thrice the Age of 'C'

Age of 'C' = 19 Years

$\sf\implies Age\: of\: 'B' = 3 \times 19 Years$

Age of 'B'  57 Years

$\sf\therefore Age\: of \:B' = 57 Years$

3) Age of 'A' = 20 years less than Age of 'B'

Age of 'B' = 57Years

Age of 'A' = 57Years - 20Years

Age of 'A' = 37Years

$\sf\therefore Required\: is\: Age\:of\: 'B' = 57years$

Answer 2

Answer:

• The age of B is 57 years.

Step-by-step explanation:

Given that:

• Age of A is 20 years less than the age of B.
• i.e., A + 20 = B ______(i)

• Age of B is thrice the age of C.
• i.e., B = 3C ______(ii)

• Age of C is half the age of D.
• i.e., 2C = D ______(iii)

• Age of D is 38 years.
• i.e., D = 38 ______(iv)

To Find:

• What is the age of B?

First finding the age of C:

• In equation (iii).

⟶ 2C = D

• Substituting the value of D from eqⁿ (iv).

⟶ 2C = 38

⟶ C = 38/2

⟶ C = 19

∴ Age of C = 19 years

Now finding the age of B:

• In equation (ii).

⟶ B = 3C

• Substituting the value of C.

⟶ B = 3 × 19

⟶ B = 57

∴ Age of B = 57 years

Finding the age of A:

• In equation (i).

⟶ A + 20 = B

• Substituting the value of B.

⟶ A + 20 = 57

⟶ A = 57 - 20

⟶ A = 37

∴ Age of A = 37 years.