Question

Age of A is three times the sum of ages of B and C. 5 years hence, A's age will be twice the sum of ages of B and C. The total of their present ages is​

Answer 1

The sum of the present ages of A , B and C is 60 years.

• Let the present ages of A , B and C be x , y and z respectively.

• Age of A is three times the sum of ages of B and C.

x = 3 (y+z)           (Equation 1)

• 5 years hence, A's age will be twice the sum of ages of B and C.

x + 5 = 2 (y+z + 10)             (Equation 2)

• Let the sum of present ages of B and C be k.

x = 3k  (Equation 3)

x + 5 = 2k+20     (Equation 4)

• Solving equation 3 and 4 we get,

5 = 20 - k

k = 15

• Now, substituting the value of k in equation 3 we get,

x = 45

• Now sum of present ages of A , B and C is x+k = 45 + 15 = 60 years.