Age of a man is 10 times to his son after 4 years his age becomes 4 times to his son find their present age in year
Answers
Answered by
10
let the age of son be x
then fathers age=10x
after 4 years:
4(x+4)=10x+4
on solving above equation we get
x=2
so there present ages are:
son=x=2years
father=10x=20 years
then fathers age=10x
after 4 years:
4(x+4)=10x+4
on solving above equation we get
x=2
so there present ages are:
son=x=2years
father=10x=20 years
Answered by
3
4(x+4)=10x+4
4x+16=10x+4
6x=12
x=2
10*2=2o
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