Question

age of a man is 5 times present age of his sum.if sum of their ages 8 years ago was 44 years,find the present age.​

Answer 1

Correct Question:

Age of a man is 5 times present age of his son. If the sum of their ages eight years ago was 44 years, find their present ages.

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Answer:

The present age of the man and his son is 50 years and 10 years respectively.

Given :

• Age of a man is 5 time present age of his son.

• Eight years ago sum of their ages was 44 years.

To find:

• Ages of the man and his son.

Solution:

Let the age of the man be x years and his son's age be y years.

According to the first condition.

=> x = 5y

=> x - 5y = 0...(1)

According to the second condition.

=> (x - 8) + (y - 8) = 44

=> x + y = 60...(2)

Subtract equation (1) from equation (2), we get

x + y = 60

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x - 5y = 0

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=> 6y = 60

=> y = 10

Substitute y = 10 in equation (1), we get

x - 5(10) = 0

=> x = 50

Therefore, the present age of the man and his son is 50 years and 10 years respectively.