Age of a man is equal to sum of ages of his three children. After 5 years twice the man’s age is 40 more than sum of ages of three children, then the present sum of ages of man and his three children is equal to:
1)45 years
2)70 years
3)35 years
3)90 years
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Correct option is
B
45 years
Let the sum of ages of two sons be x years
Age of man = 3xyears
After 5 years age of the man =(3x+5)years
Sum of ages of two sons =(x+10)years
Given, (3x+5)=2(x+10)
⇒ (3x+5)=2x+20
⇒ x=15
Hence 3x=3(15)=45
∴ Present age of father is 45years.
B
45 years
Let the sum of ages of two sons be x years
Age of man = 3xyears
After 5 years age of the man =(3x+5)years
Sum of ages of two sons =(x+10)years
Given, (3x+5)=2(x+10)
⇒ (3x+5)=2x+20
⇒ x=15
Hence 3x=3(15)=45
∴ Present age of father is 45years.
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