Age of a man is three times the age of his son. After 10 years, the age of the man will be double that of the son. Assuming the age of the son to be X, obtain a relation and find their present ages.
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Answer:
Son ( X ) = 20 years
His Father = 40 years
before 10 years
son was 10 years and his father was 3×10 = 30
after 10 years
son was 20 years and his father was 20×2 = 40 years
so this gives conclusion that
son is 20 years now
his father is 40 years now
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