Question

Age of a mother is 1/4 the age of her daughter . lf the difference of their ages is 36 yrs,find their ages

Answer 1

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Answer 2

let the age of daughter be x
$x - \frac{1}{4} = 36 \\ x = 36 + \frac{1}{4} \\ x = \frac{144 + 1}{4} \: \: \: on \: cross \: multiplication \\ x = \frac{145}{4} \\ \\ hence \: daughters \: age \: is \: \frac{145}{4}$