Age of egyptian papyrus with 71% of its original c-14 atoms
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Age will be 5700 years.
y = a(1/2) ^ t/p
where ,
a : original value of the C - 14 .
t : amount of time it takes for the C - 14 to decay to y amount .
p : half-life period .
71 / 100 = 0.71
0.71 = 1 / 2 ^ t / p
log ( 1 / 2 ) x 0.63 = t / p
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