Age of father is 3 times the sum of his two daughters age.After 5 years the age of father will be double the sum of his two daughters age.find the father present age.
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Let the age of father be x years and sum of the ages of two children be y years .
According to question:
Father's age is three times the sum of his two children.
⇒x=3y ........(1)
After 5 years -
Father's age = (x+5) years
Sum of the ages of two children = (y+5+5) years = (y+10) years
According to question:
⇒(x+5)=2(y+10)
Putting x = 3y from (1) to (2),we get:
⇒3y+5=2y+20
⇒3y−2y=20−5
⇒y=15
Putting y = 15 in (1),we get
⇒x=3×15
⇒x=45
Thus,the age of father = 45 years
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