Question

Age of Father is 3times of his son's age now.His age was 6 more than 4 times of son's age 2 years ago.Find their ages.

Answer 1

Answer:

Let the present age of the father be x years. Let the present age of the son be y years. After 4 years, the father's age is four times his son's age. Therefore, the present ages of the father and the son are 36 years and 6 years.

Step-by-step explanation:

Solution:

Given, the father's age is six times his son’s age.

We have to find the present ages of the father and the son.

Let the present age of the father be x years.

Let the present age of the son be y years.

Given, x = 6y ------------- (1)

After 4 years, the father's age is four times his son’s age.

(x + 4) = 4(y + 4)

x + 4 = 4y + 16

x - 4y = 16 - 4

x - 4y = 12 ----------- (2)

For solving the linear equations (1) and (2), substitute (1) in (2),

6y - 4y = 12

2y = 12

y = 12/2

y = 6

Put y = 6 in (1),

x = 6(6)

x = 36

Therefore, the present ages of the father and the son are 36 years and 6 years.