Math, asked by auroraariazen, 10 months ago

age of father is 4 times the age of his son 5 years hence the age of father will be three times the age of his son find their present ages


auroraariazen: Use elimination method

Answers

Answered by kanchankashyap14
0

Answer:

Step-by-step explanation:

F/S=4/1 and F/S=3/1

Diff bwt ratio make equal so

8/2and 9/3

Diff betw 8-9 is 1= 5 yrs

So 8=40 yrs

2= 10 yrs


auroraariazen: Use elimination method frame an equation
auroraariazen: 2 equations shud be thr
Answered by Anonymous
11

Answer:

Let the present age of son be x years and present age of father will be 4x years.

According to Question now,

➳ 3(x + 5) = 4x + 5

➳ 3x + 15 = 4x + 5

➳ 15 - 5 = 4x - 3x

➳ x = 10 years

Therefore,

Present age of son = x = 10 years

Present age of father = 4x = 40 years

Similar questions