Question

Age of father is 6 times the age of his son after 20 yearsthe fayher age will be twice the son age .What is the present age of son

Answer 1

Let the present age of son be x

Let the present age of his father be 6x

After 20 years, age of son = x + 20

After 20 years, age of his father = 6x + 20

In 20 years, father will be twice the age of son = 2(x + 20) = 2x + 40


According to the question,

6x + 20 = 2x + 40

6x - 2x = 40 - 20

4x = 20

x = $\dfrac{20}{4}$

x = 5



Present age of son => x years

=> 5 years ✔

Answer 2

Answer:

5 years.

Step-by-step explanation:

• Let the age of his son be x years.
• So His age = 6 x years.

A/Q , (x + 20)2 = 6 x + 20

⇒ 2 x + 40 = 6 x + 20

⇒ 4 x = 20

∴ x = 5.