Math, asked by snehabaldha90, 1 month ago

age of father os 40 years while his sons age is 10 year. after how many years will the age of the father be twice the sons age . solve it blade girl​

Answers

Answered by chouhancharanpreet
0

Answer:

the son's age be x

Then , according to the condition,

father's age =3x+3

3 years later:

Son's age =x+3

Father's age =3x+3+3=3x+6

According to the condition given ,

3x+6=10+2(x+3)

3x+6=10+2x+6

x=10

Thus , the son's present age is 10 years and the father's age is

3x+3=3×10+3=33 years.

Answered by mahadeorao13
0

Answer:

50 years

Step-by-step explanation:

40 s twice means to add a 40 again so add 40 to 10 as well

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