Age of John’s Father is 3 times John’s age. After 5 years, he will be twice the age
of John. Find their ages after four years?
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Answer:
Let Johns age be x years
So, his fathers age is 3x years
Johns age after 5 years = (x + 5) years
His fathers age after 5 years = (3x + 5) years
So, 2(x + 5) = 3x + 5
2x + 10 = 3x + 5
2x - 3x = -10 +5
-x = -5
x = 5
Johns present age = 5 years
Johns fathers age = 15 years
Johns age after 4 years = 9 years
His fathers age after 4 years = 19 years
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