Question

Age of leena and heena are in the ratio 7:5 . Ten years hence , there ages will be 9:7 . Find their present ages .

Answer 1

let common ratio be x
7x/5x= 7/5

After 10 yrs;
7x + 10/5x+10 = 9/7
49x + 70 = 45x + 90
4x = 20
x = 5

their present are;
7x = 7×5 =35yrs
5x = 5×5= 25yrs

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Answer 2

Step-by-step explanation:

Answer:

The Present ages are -

Leena = 35 years

Heena = 25 years

Step-by-step explanation:

Given :

Ages of Leena and Heena are in Ratio = 7 : 5

Ratio after 10 Years = 9 : 7

To Find :

Their present Ages

Solution :

Let the present Ages be -

• Leena as 7x
• Heena as 5x

$\rule{300}{1.5}$

➡ (7x + 10)/(5x + 10) = 9/7

➡ 7(7x + 10) = 9(5x + 10)

➡ 49x + 70 = 45x + 90

➡ 49x - 45x = 90 - 70

➡ 4x = 20

➡ x = 20/4

➡ x = 5

$\rule{300}{1.5}$

Heena's age =

➡ 5 × 5

➡ 25

$\rule{300}{1.5}$

Leena's age =

➡ 7 × 5

➡ 35

$\therefore$ The Present ages are -

• Leena = 35 years
• Heena = 25 years