Question

age of Leena and Heena are in the ratio 7 by 5 10 years hence the ratio of their ages will be 9 by 7 find their present ages​

Answer 1

Answer:

Step-by-step explanation:

Let the age of Leena = 7x years

Let the age of Heena= 5x years

Hence,

The required linear equation:-

7x+10/5x+10=9/7

=>9(5x+10)=7(7x+10)

=>45x+90=49x+70

=>90-70=49x-45x

=>20=4x

=>5 =x

Age of Leena = 7x =35 years

Age of Heena = 5x = 25 years

Answer 2

SOLUTION :

⇒ LET THE AGE OF LEENA BE 7x

⇒AND THE AGE OF HEENA BE 5y

⇒Ten year hence

I.e. 7x+10 and 5x+10

7x+10/5x+10=9/7

By cross multiplication, we get

49x+70=45x+90

4x=20

x=5

⇒Therefore ages are

7×5=35 and 5×5=25

ANSWER--- The present age of leena is 35yrs and the present age of Heena is 25yrs