Math, asked by Anonymous, 6 months ago

age of man is three times age of son. after 10 years, the age of the man will be double that of son. find their present ages.
pls guys i need it fast

Answers

Answered by amansharma264
47

EXPLANATION.

  • GIVEN

Age of man is three times age of son.

After 10 years,the age of the man will be double

that of son.

Find their present age.

According to the question,

Case = 1

Age of man is three times age of son.

Let the present age of son be = x years.

Let the present age of man be = 3x years.

Case = 2

After 10 years, the age of man will be

double that son.

=> 3x + 10 = 2 ( x + 10 )

=> 3x + 10 = 2x + 20

=> x = 10

Therefore,

Present age of son = 10 years.

present age of man = 3(10) = 30 years.

Answered by Anonymous
42

Answer:

Present age of son is 10 years and man is 30 years

Step-by-step explanation:

Assume that the present age of son is x years.

Age of man is three times age of son. Therefore, the age of man is 3x years.

As per given condition,

After 10 years, the age of man will be

double that son.

→ 3x + 10 = 2(x + 10)

→ 3x + 10 = 2x + 20

→ 3x - 2x = 20 - 10

→ x = 10

Hence, the present age of:

Son = x = 10 years

Man = 3x = 3(10) = 30 years

Verification

Substitute value of x = 10 in 3x + 10 = 2(x + 10)

3(10) + 10 = 2(10 + 10)

30 + 10 = 2(20)

40 = 40

L.H.S. = R.H.S.

Hence, proved.

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