Question

Age of Mohit is 7 times his son. After 10 years his age becomes 3 times then find the present age of son?​

Answer 1

Step-by-step explanation:

let present ages of Mohit and his son ages are f and s respectively.

According to the problem, f=7s and f+10=3(s+10).

==> f+10=3(s+10)==> 7s+10=3s+30==>s=5.

and f=35.

Therefore the difference in their present ages=35-5=30years.