Question

Age of mother 10 years ago was 3 times the age of her son. After 10 year, mother's age will be twice that of his son.Find the ratio of their present ages

Answer 1

hope this will help you


so the ratio is 70/30 i.e 7:3

Answer 2

Let the son's present age be x

So 10 yrs ago son's age = x - 10

Given that age of mother ten years ago was 3 times of son

=> mother's age 10 yrs ago = 3(x - 10)

= 3x - 30

After 10 yrs, son's age would be x + 10

Given after ten yrs, mother's age would be twice of the son

=> mother's age = 2(x + 10)

= 2x + 20

But 10 yrs ago of present time, her age was 3x - 30

So it will take 20 yrs to go 10 yrs in future from the present age.

=> 3x - 30 + 20 = 2x + 20

=> 3x - 10 = 2x + 20

=> 3x = 2x + 20 + 10

=> 3x - 2x = 30

=> x = 30.


Present age of son = 30 yrs.

=> 10 yrs ago mother's age =

3x - 30

= 3(30) - 30

=> 90 - 30

= 60 yrs.


So present age of mother = 60 + 10 = 70 yrs


Ratio =

mother : son

= 70 : 30

= 7: 3

Hope you understand