Math, asked by Bsndndkdkdjjdjr436, 1 day ago

Age of mother is 13 times the age of her daughter.it will be 5 times after four years. Find the present ages.

Answers

Answered by zoyafirdous20913
0

Answer:The present age of the daughter is 2 years.

The present age of the mother is 26 years.

Answered by shabeehajabin
0

Answer:

The present age of mother is 26 years and the daughter is 2 years.

Step-by-step explanation:

Given that the age of the mother is 13 times the age of her daughter. It will be 5 times after four years. The question is to find the present age.

Let the present age of the daughter be 'x'

Then the age of the mother = 13\tiimes x

The age difference = 13\tiimes x-x

The age of the daughter after 4 years = x+4

Therefore the age of the mother after 4 years = 5(x+4)

The age difference=5(x+4)-(x+4)

Now we have two equations for the age difference, equate these two to find 'x'. That is,

      13\tiimes x-x=5(x+4)-(x+4)

           12x=5x+20-x-4\\\\12x=4x+16\\

           \begin{array}{l}12x-4x=16\\\\8x=16\\\\x=\dfrac{16}{8}\\\\x=2\end{array}

Hence the daughter is 2 years old.

Therefore the present age of the mother = 13\tiimes x =13\times 2=26 years

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