Question

Age of nandu is 10 more than that age of anu age of manu is 3 year more than twice the age of nandu. The sum of their age is 53. Find the their ages? (Hind: take the age of nandu as x

Answer 1

Answer:-

Given:

• Age of nandu 10 more than that of Anu.
• Manu is 3 years more than twice the age of Nandu.

Sum of the ages of three = 53 years.

Let Nandu's age be x years.

So,

→ Anu's age = (x - 10) years

→ Manu's age = (2x + 3) years.

According to the question,

→ x + x - 10 + 2x + 3 = 53

→ 4x = 53 + 10 - 3

→ 4x = 60

→ x = 60/4

→ x = 15

Hence,

• Age of Nandu = x = 15 years.

• Age of Anu = x - 10 = 15 - 10 = 5 years.

• Age of Manu = 2x + 3 = 2(15) + 3 = 30 + 3 = 33 years.

Answer 2

$\huge\mathbb{\underline{SOLUTION:-}}$

$\sf\underline{\purple{Given:-}}$

• Age of nandu is 10 more than that age of anu age

• Manu is 3 year more than twice the age of nandu. The sum of their age is 53

$\sf\underline{\purple{To\:Find:-}}$

• Their Ages

$\: \: \:\:\: \: \circ \: \underline{\boxed{\red{\scriptsize{ \sf Hint: take \: the \: age \: of \: nandu \: as \: x}}}}$

$</p><p></p><p>\sf\underline{\purple{Solution:-}}$

Nandu age is 10 years more than Anu

Manu is Twice 3 year more than nandu =

2x + 3

The sum of their age is = 53

4x = 53 + 10 - 3

So 4x = 60

x =$\sf \frac{60}{4}$

So x = 15

Hence,

• Age of Nandu = 15 years

• Age of Anu = 5 years

• Age of Manu = 33 years