Question

Age of Nandu is 10years more than that of Anu . Age of many 3years more than twice the age of Nandu . The sum of their age is 53.find their age ?(take age of Nandu as X)

Answer 1

Answer:

Nandu = 10+ Anu i)

Manu = 3+2 x Nandu

substitute equation i)

Manu = 3 + 2 (10 + Anu)

Anu + Nandu+ Manu = 53

= Anu + 10 +Anu +3 + 2 (10 + Anu) = 53

Anu + 10 + Anu +3 + 20 + 2 Anu = 53

4Anu =23 = 53

4Anu = 20

Anu = 5 years old

Nandu= 15 years old

Manu = 33 years old

Answer 2

Given:−

Age of nandu is 10 more than that age of anu age

Manu is 3 year more than twice the age of nandu. The sum of their age is 53

$\sf\underline{\purple{To\:Find:-}}$

Their Ages

$\: \: \:\:\: \: \circ \: \underline{\boxed{\red{\scriptsize{ \sf Hint: take \: the \: age \: of \: nandu \: as \: x}}}}∘$

$</p><p> </p><p></p><p>\sf\underline{\pink{Solution:-}}$

Nandu age is 10 years more than Anu

Manu is Twice 3 year more than nandu =

2x + 3

The sum of their age is = 53

4x = 53 + 10 - 3

So 4x = 60

$x =\sf \frac{60}{4}$

So x = 15

Hence,

• Age of Nandu = 15 years
• Age of Anu = 5 years
• Age of Manu = 33 years