Math, asked by guruprasad54, 11 months ago

age of radha is 3times the age of Reena. After 12years, the age of radha will be two times of Reena Find the age of Radha & Reena after 3years.​

Answers

Answered by khushi2050
0

Let Reena's age be be x years

Radha's age=3x years

After 12 years,Reena age =(x+12)years

radha age=(3x+12)years

According to question,

3x+12=2(x+12)

3x+12=2x+24

x=12=reena's present age

radha present age =36 years

After 3 years,reena will be of 15 years nd age of reena will be 39 years...

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Answered by atharv8045
0

Step-by-step explanation:

Let the Reena age is to be x

& the Radha age is to be 3x

By first given condition

after 12 years,

age of Radha is 3x+12

age ofReena is x+12

By given condition

2(12+x)= (3x+12)

24+2x= 3x+12

24-12=3x-2x

12=x

age of Radha=3×12

=36

age of Reena =12

After 3years

age of Radha= 36+3

=39 years

age of Reena=12+3

=15 years

Answered by atharv8045
1

Step-by-step explanation:

Let the Reena age is to be x

& the Radha age is to be 3x

By first given condition

after 12 years,

age of Radha is 3x+12

age ofReena is x+12

By given condition

2(12+x)= (3x+12)

24+2x= 3x+12

24-12=3x-2x

12=x

age of Radha=3×12

=36

age of Reena =12

After 3years

age of Radha= 36+3

=39 years

age of Reena=12+3

=15 years

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