Math, asked by guruprasad54, 1 year ago

age of radha is 3times the age of Reena. After 12years, the age of radha will be two times of Reena Find the age of Radha & Reena after 3years.​

Answers

Answered by khushi2050
0

Let Reena's age be be x years

Radha's age=3x years

After 12 years,Reena age =(x+12)years

radha age=(3x+12)years

According to question,

3x+12=2(x+12)

3x+12=2x+24

x=12=reena's present age

radha present age =36 years

After 3 years,reena will be of 15 years nd age of reena will be 39 years...

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Answered by atharv8045
0

Step-by-step explanation:

Let the Reena age is to be x

& the Radha age is to be 3x

By first given condition

after 12 years,

age of Radha is 3x+12

age ofReena is x+12

By given condition

2(12+x)= (3x+12)

24+2x= 3x+12

24-12=3x-2x

12=x

age of Radha=3×12

=36

age of Reena =12

After 3years

age of Radha= 36+3

=39 years

age of Reena=12+3

=15 years

Answered by atharv8045
1

Step-by-step explanation:

Let the Reena age is to be x

& the Radha age is to be 3x

By first given condition

after 12 years,

age of Radha is 3x+12

age ofReena is x+12

By given condition

2(12+x)= (3x+12)

24+2x= 3x+12

24-12=3x-2x

12=x

age of Radha=3×12

=36

age of Reena =12

After 3years

age of Radha= 36+3

=39 years

age of Reena=12+3

=15 years

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