Question

Age of Ramya and double the age of Sophie added together gives 28 three fourth of Ramya age added to words for the of one fourth of Sofia sage gives 11 find the age of Ramya and Sophie

Answer 1

Answer:

Ramya: 12; Sophie: 8

Step-by-step explanation:

Let the age of Ramya be x and that of Sophie be y.

Then,

x+2y = 28 [age of Ramya (x) + double the age of sophie (2y)] .......... EQ. 1

and

3x/4 + 1y/4 = 11 [3/4th of Ramya's age added to 1/4th of Sophie] ............. EQ. 2

Solving eq. 1 & 2, we get:

x = 12 &

y = 8.

Hence, Ramya's age is 12 and Sophie's age is 8.

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Answer 2

Given,

Let, $x$ be the age of Ramya and $y$ be the age of Sophie.

Age of Ramya and double the age of Sophie added together gives $28$.

$x+2y=28$

$x=28-2y$ ______(1)

Three fourth of Ramya age added to words for the of one fourth of Sophies age gives $11$

$\frac{3}{4}x+\frac{1}{4}y=11$

$3x+y=44$_____(2)

Substitute equation (1) in equation (2)

$3(28-2y)+y=44$

$84-6y+y=44\\5y=84-44\\5y=40\\y=8$

Substitute $y=8$ in equation (1)

$x=28-2\times8\\x=28-16\\x=12$

Therefore, the ages of Ramya ad Sophie are $12$ and $8$.