Age of Remya and double the age of sofi added together gives 28 . Three - fourth of Remya's age added to one - fourth of sofi's age gives 11. Find the age of Remya and the age of sofi . step by step please
Answers
Answer:
Let remya age be x and sofia age be y
ATQ to 1st statement :-
2y + x = 28 --- ( i )
ATQ to 2nd statement
3/4 x + 1/4y = 11
3x + y / 4 = 11
3x + y = 44 ------- ( ii )
Multiply eq ( i ) by 3
6y + 3x = 84 ----- ( iii )
Subtracting ii from iii
6y + 3x - 3x - y = 84 - 44
5y = 40
y = 40 / 5
y = 8
y = 8
putting value of y in eq i
2y + x = 28
2 x 8 + x = 28
16 + x = 28
x = 28 - 16
x = 12
x = 12
Therefore remya's age = x = 12 years
sofi's age = y = 8 years
Answer:
Sum of ages of remya and double age of sofi is 28 .
Sum of ages of 3/4 of remya's age and 1/4 of sofia's age is 11
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ToFind
Current age of remya and sofia = ??
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Solution
Let remya age be x and sofia age be y
ATQ to 1st statement :-
2y + x = 28 --- ( i )
ATQ to 2nd statement
3/4 x + 1/4y = 11
3x + y / 4 = 11
3x + y = 44 ------- ( ii )
Multiply eq ( i ) by 3
6y + 3x = 84 ----- ( iii )
Subtracting ii from iii
6y + 3x - 3x - y = 84 - 44
5y = 40
y = 40 / 5
y = 8
y = 8
putting value of y in eq i
2y + x = 28
2 x 8 + x = 28
16 + x = 28
x = 28 - 16
x = 12
x = 12
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Answer
Therefore remya's age = x = 12 years
sofi's age = y = 8 years