Question

age of sister is twice the age of brother 3year back age of the sister was three time the age of the brother .find there present ages​

Answer 1

let age of brother =x

age of sister = 2x

three years back........

age of brother = x-3

age of sister = 2x-3

According to question,

$2x - 3 = 3(x - 3) \\ 2x - 3 = 3x - 9 \\ 2x - 3x = - 9 + 3 \\ - x = - 6 \\x = 6$

present age of brother = x = 6 years

present age of sister = 2x = 12 years

Mark this answer as a brainliest answer !!!

Answer 2

Answer:

x=12,y=6

Step-by-step explanation:

x=2y(present)

x-3=3(y-3)->past

by subs x we get

2y-3=3y-9

2y-3-3y+9=0

-y+6=0

-y=-6

y=6

subst in x, then we get

x=12