Question

Age of son is1/4 the age of his father. If the difference of their ages is 36 years

find their ages.​

Answer 1

Answer:

given, age of son is one fourth the age of his father

let the father's age be x years and the sons age be x/4 years.

ATQ,

x minus x/4 = 36

4x/4 minus x/4 = 36

3x/4 = 36

3x = 36*4

3x = 144

x = 144/3

x = 48 = father's age

x/4 = 12 = sons age

Answer 2

Answer:

age of father is 48 and age of son is 12