Age of x is 3 year more than twice the age of y, if age of y is 10 year find age of x
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Answer:
Let the son's age be x
Then , according to the condition,
father's age =3x+3
3 years later:
Son's age =x+3
Father's age =3x+3+3=3x+6
According to the condition given ,
3x+6=10+2(x+3)
3x+6=10+2x+6
x=10
Thus , the son's present age is 10 years and the father's age is
3x+3=3×10+3=33 years.
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