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Q3.) 90+x+2x=180° (ASP of triangle)
3x = 90°
x = 30°
Therefore angles are 30° and 2x = 60°
Q4.) 30+122+x=180° (ASP of triangle)
152+x=180°
x=28°
Q5.) Let the other 2 angles be 1x and 2x (Since angles are in the ratio 1:2)
x+2x+60=180° (ASP of triangle)
3x=120°
x=40°
Therefore the angles are 40° and 2x = 80°
Q6.) Since CD || AB and AC is the transversal
Angle BAC = Angle ACD (Alternate Interior Angles)
=> x = 70°
40+x+y=180° (ASP of triangle)
40+70+y=180°
110+y=180°
y=70°
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