Question

Ages of father and son are in the ratio 3:5. Find their ages after 5 years

Answer 1

Step-by-step explanation:

Let the age of father be x years now and that 9f son be Y years now.

Then according to question,

[math]x/y = 5/3[/math]

Or [math]3x = 5y.[/math] {1}

But, after 10 years ratio of their age is [math]3/2.[/math]

Thus, mathematically :

[math](x+10)/(y+10)=3/2[/math]

[math]2x+20 = 3y+30[/math]

[math]2x-3y=10.[/math]

Going back to equation 1 we have [math]3x=5y [/math]or [math]y=3x/5[/math]

Put the above value of Y in equation 2 to get value of x which is the father's age.

[math]2x-3(3x/5) = 10[/math]

[math]2x-9x/5 =10[/math]

[math](10x-9x) = 50[/math]

X=50

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