Question

Ages of joy and Rohit are in the ratio 5:7 . After 10 years, age of Rohit and joy will be 7:9.Find the present ages.​

Answer 1

Answer:

Let the age be x

So, present age of joy is 5x

and present age of Rohit is 7x

After 10 years,

Age of joy = 5x+10

Age of Rohit = 7x+10

According to the question,

5x+10/7x+10 = 7/9

9(5x+10) = 7(7x+10)

45x+90 = 49x+70

90-70 = 49x-45x

20 = 4x

x = 5

Present age of joy = 5×5 = 25years

Present age of Rohit = 7×5 = 35years

Answer 2

$\bf{\underline{Given:-}}$

• Age of joy and rohit in ratio 5 : 7

After 10 years ..

• Age of rohit and joy will be 7 : 9

$\bf{\underline{To \:Find}}$

• Let the present age of Rohit be 5x years.
• And present age of Joy be 7x years.

After 10 years ago,

→ Age of Rohit 5x + 10

→ Age of joy 7x + 10

ACCORDING TO THE QUESTION

$\bf → \large\frac{5x + 10 }{ 7x + 10} = \frac{7}{9}$

→ 9(5x+10) = 7(7x+10)

→ 45x + 90 = 49x + 70

→ 90 - 70 = 49x - 45x

→ 20 = 4x

→ x = 5

$\bf{\underline{Hence:-}}$

• Present age of joy = 5x = 5 × 5 = 25years

• Present age of Rohit = 7x = 7 × 5 = 35years