Question

ages of Lena and heena are in the ratio 7 : 10 years hence the ratio of their ages will be 9:7 find their present ages?

Answer 1

let L=Leena's present age
let H=Heena's present age
at present:
L/H=7/5
H=5L/7
10 yrs hence:
L+10=Leena's age
H+10=Heena's age
(L+10)/(H+10)=9/7

7L+70=9H+90
7L-9H=20
sub L for H
7L-9*5L/7=20
7L-45L/7=20
49L-45L=140
4L=140
L=35
H=5L/7=25
Leena's present age=35
Heena's present age=25

Answer 2

Answer:

The Present ages are -

• Leena = 35 years
• Heena = 25 years

Step-by-step explanation:

Given :

Ages of Leena and Heena are in Ratio = 7 : 5

Ratio after 10 Years = 9 : 7

To Find :

Their present Ages

Solution :

Let the present Ages be -

• Leena as 7x
• Heena as 5x

$\rule{300}{1.5}$

➡ (7x + 10)/(5x + 10) = 9/7

➡ 7(7x + 10) = 9(5x + 10)

➡ 49x + 70 = 45x + 90

➡ 49x - 45x = 90 - 70

➡ 4x = 20

➡ x = 20/4

➡ x = 5

$\rule{300}{1.5}$

Heena's age =

➡ 5 × 5

➡ 25

$\rule{300}{1.5}$

Leena's age =

➡ 7 × 5

➡ 35

$\therefore$ The Present ages are -

• Leena = 35 years
• Heena = 25 years